Correct! The positive entropy change of step 1 means elevating the temperature will make the reaction more product-favored. In reality, for technical reasons the ore and coal are baked at 1400-1500 ºC instead of only 1200 ºC. Click on the Next button below to return to the Problem-Solving Page or on the Close button to close this window.
Step 1 is predicted to become product-favored at 1180 ºC. See the solution below. The positive entropy change of step 1 means elevating the temperature will make the reaction more product-favored. In reality, for technical reasons the ore and coal are baked at 1400-1500 ºC instead of only 1200 ºC. Click on the Next button below to return to the Problem-Solving Page or on the Close button to close this window.
DGº=DHº - TDSº < 0
2851.9 kJ - T•(1967.72 J/K • 1kJ/1000J) < 0
-1.96772T kJ/K < -2851.9 kJ
T > 2851.9 kJ/(1.96772 kJ/K)
T > 1450 K=1180 ºC
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