HOAc 
H+ + OAc-
K = 1.8x10-5 =
[H+][OAc-]
[HOAc]
[H+] = K
[HOAc]
[OAc-]
Let's rearrange this equilibrium expression to solve for [H+}
|
HOAc |
|
|
K = 1.8x10-5 = |
[H+][OAc-] [HOAc]
|
|
[H+] = K |
[HOAc] [OAc-]
|
This says that the hydrogen ion concentration, [H+] is
proportional to the [HOAc] / [OAc-] ratio.
Next, let's explore what happens if we add a little acid or base.
