HOAc 
H+ + OAc-
K = 1.8x10-5 =
[H+][OAc-]
[HOAc]
=
[H+][0.10]
[0.10]
We found that if we use 0.10 M acetic acid and 0.10 M
sodium acetate the concentrations cancel in the equilibrium
equation.
|
HOAc |
|
|
K = 1.8x10-5 = |
[H+][OAc-] [HOAc]
|
|
= |
[H+][0.10] [0.10]
|
If we double the acetic acid and sodium acetate concentration
so [HOAc] is 0.2) M and [OAc-] = 0.20 M what is the new hydrogen
ion concentration?
