How are buffers made?
A buffer must contain a weak acid and its conjugate base. There are several ways a solution containing these two components can be made:
Buffers can be made from weak acids or base and their salts.
For example, if 12.21 grams of solid sodium benzoate are dissolved in 1.00 L 0.100 M benzoic acid (C6H5COOH, pKa = 4.19) solution, a buffer with a pH of 4.19 will result:
Buffers can be made from two salts that provide a conjugate acid-base pair.
A buffer can be made by dissolving 15.0 grams NaH2PO4 and 17.7 grams Na2HPO4 in water and diluting to 1.00 liter.
What
will be the pH of this buffer (molecular weight of NaH2PO4
is 120.0 g/mol, molecular weight of Na2HPO4 is 142.0
g/mol)?
H3PO4 + H2O
H2PO4- + H3O+ Ka1
= 7.1 x 10-3
H2PO4- + H2O
HPO42- + H3O+ Ka2
= 6.3 x 10-8
HPO42- + H2O
PO43- + H3O+ Ka3
= 7.1 x 10-13
The
acid in this buffer is H2PO4- and
the conjugate base is HPO42-. Which ionization
reaction is an equilibrium between these two species?
Good!
Buffers can be made by adding a strong acid or base to a weak acid or base.
If a strong acid such as HCl is added to NH3 (a weak base), NH4+ (the conjugate acid of NH3) is produced:
H+ + NH3
NH4+
If
50.0 mL 0.10 M HCl is added to 100.0 mL 0.10 M NH3, what are
the resulting concentrations of NH3 and NH4+?
The
added HCl will react with NH3 to produce NH4+.
How many moles of HCl are added? How many moles of NH4+
will be produced? How many moles of NH3 will remain?
Good!
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