Stoichiometry Module: ICE Tables
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Step 3: If any of the known information is given as a mass or volume, convert to moles.

How many grams of NaNO3 are produced when 5.3 grams of Na2CO3 are added to 250.0 mL of 0.50 M HNO3 and the reaction is allowed to go to completion?

Na2CO3 (aq) + 2 HNO3 (aq) 2 NaNO3 (aq) + CO2 (g) + H2O (l)

The next step is convert any known information to moles.

How many moles of Na2CO3 are present in 5.3 grams (molecular weight of Na2CO3 is 106.0 g/mol)?

.050 moles .50 moles 1.0 mole 560 moles

Good! Grams can be converted to moles by dividing by the molecular weight:

Remember that grams can be converted to moles by dividing by the molecular weight. Try again.









How many moles of HNO3 are present in 250.0 milliliters (concentration of this solution is 0.50 M)?

.0125 moles .125 moles 1.25 moles 0.50 moles

Remember to first convert milliliters to liters (1 L = 1000 mL). Try again.

Liters can be converted to moles by multiplying by the molarity. Try again.

Good! Volume can be converted to moles by multiplying by the concentration:

The ICE Table with this information looks like:

Na2CO3 + 2 HNO3 2 NaNO3 + CO2 + H2O
Initial amount 5.3 g 250.0 mL 0 0 0
Initial (moles) .05 moles .125 moles 0 0 0
Change (moles)
End (moles)
End amount