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Goal: to recognize and construct oxidation and reduction half-reactionsWorking Definition:
An equation is worth 6.022 x 1023 wordsWhen a nickel strip {Ni (s)} is placed in an aqueous solution of copper(II) sulfate {Cu2+, SO42-}, an immediate reaction occurs. Copper metal begins to deposit on the strip. The only source for metallic copper in this system is the copper(II) ions in solution. What is happening to the copper(II) ions to cause them to change into elemental copper? Let's represent this fascinating observation with a chemical equation:
We have just written a half-reaction! In this
equation, the copper(II) ion is being reduced {2+
If copper(II) ion is being reduced, what is being oxidized? Another way to ask this question is 'where are those electrons coming from?'. Nickel, of course! What is the half-reaction for the oxidation of metallic nickel? Nickel must release 2 electrons to form the nickel(II) ion as shown in the following equation (remember that we balance the mass and then the charge):
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![]() Did you remember to balance the bromine (first) in the last question? Let's solve another one... Cadmium's ContributionCadmium is a silvery, crystalline metal resembling zinc. A large part of the cadmium produced in the United States is used in electroplating metals, such as iron and steel, to protect them from corrosion. The process usually involves the half-reaction shown below. Balance this equation so that we can preserve our steel. Be careful of the cyanide! Before moving to the next page you should know how to write and balance a simple oxidation and reduction half- reaction. |
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