Thermodynamics:
Free Energy

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In this module:
Introduction
DG and Reactions
DG and Temperature
DGfº
Coupling Reactions
Free Energy in Industry
Free Energy in Living Things
Free Energy and Equilibrium

Free Energy in Industry

Many, many products in industry are made by reactant-favored reactions. Each of these reactions must be coupled to a product-favored reaction in order to be useful. Most of these reactions fall into one of two classes:

1. Purifying metals or other elements from their ores. Metals are usually found in one of their oxidized states in their ores. These metals must be reduced in reactant-favored processes in order to be purified.

2Fe2O3(s) 4Fe(s) + 3O2(g) DGº = 742.2 kJ
2NaCl(s) 2Na(s) + Cl2(g) DGº = 384.138 kJ
HgS(s) + O2(g) Hg() + SO2(g) DGº = -249.594 kJ

2. Raw materials for other products. The most important raw material in the plastics industry is the alkene ethene (ethylene). It is produced in a reactant-favored reaction from ethane:

C2H6(g) H2(g) + C2H4(g)     DGº = 100.97 kJ

Sodium hydroxide and chlorine gas, both used in many industrial processes including the production of paper, are produced from a simple sodium chloride solution:

2NaCl (aq) + 2H2O() 2NaOH(aq) + Cl2(g) + H2(g)     DGº = 422.22 kJ

Most of these reactions are made product-favored by heat or electricity. Where does the energy used to drive these reactions come from? Both the heat and electricity usually come from the burning of fossil fuels, e.g. coal:

C(s) + O2(g) CO2(g)     DGº = -394.359 kJ

methane (natural gas):

CH4(g) + 2O2(g) CO2(g) + 2H2O(g)     DGº = -800.78 kJ

or oil:

C17H36(l) + 26O2(g) 17CO2(g) + 18H2O(g)     DGº < -20,000 kJ

Calculate the heat released by burning 1.00 kg of coal.

Correct! The solution is shown below.
That is incorrect. Try again.
The solution is shown below.
In thermochemical equations, the change in the thermodynamic quantity can be used in a stoichiometric ratio with any of the reactants or products. Therefore:

1.00 kg C(s) • 1000 g/1 kg • 1 mol/12.01 g • -394.359 kJ/1 mol = -32800 kJ

Is this heat sufficient to reduce 1.00 kg of iron(III) oxide to iron metal?

Yes
No
Correct! The solution is shown below.
That is incorrect. The explanation is shown below.

-32800 kJ • 2 mol Fe2O3/742.2 kJ • 159.7 g/1 mol • 1 kg/1000 g = 14.1 kg

Free Energy in Industry